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15k^2=6k
We move all terms to the left:
15k^2-(6k)=0
a = 15; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·15·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*15}=\frac{0}{30} =0 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*15}=\frac{12}{30} =2/5 $
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